How many ways can you seat 10 people in a row?

How many ways can you seat 10 people in a row?

= 3265920 ways for the ten people to be seated so that a certain to are not next to each other.

How many ways can 10 people sit at a circular table so that 2 particular people are always opposite to each other?

So there are 10*40320=403200 ways to sit the 10 people so that 2 predetermined persons always sit across each other in a round table with 10 seats.

Can 10 people sit at one table?

8-10 people can fit at an 8′ table. If you seat 10, the people on the end will not be able to slide their chairs under the table. If you have formal place settings, you definitely can’t fit more than 8.

How many ways can 10 people sit in a round table with 10 seats?

But there are 10 possible such points. So there are 10 ways of seating 10 people abreast for every way of seating them at a round table. It follows that the number of ways of seating 10 people at a round table = 10!/10 = 9! = 362,880.

How many ways are there if two of the persons are not allowed to sit next to each other?

That can be done in 2⋅6! =1440 ways.

How many chairs can fit around a 60 round table?

A 60” Round Table can comfortably seat 8 guests. Reducing the seating to 6 will give your guests more space. Many rental companies will state that a 60” Round Table can accommodate 8-10 guests. Although this is true, 10 chairs would be rather tight.

How many ways can 7 people sit in a circular table?

Complete step-by-step answer: Since in this question we have to arrange persons in a circle and 7 persons have to be arranged in a circle so that every person shall not have the same neighbor. Hence there are 360 ways to do the above arrangement and therefore the correct option is A.

How big is a round table that seats 10?

8 feet
What size round table seats 10? A round table that’s 8 feet in diameter can seat 10 to 12 people.

How many people can sit at a round table?

There are 6 people, let’s call them – (a,b,c,d,e,f), to sit at a round table. The number of ways they can arrange themselves is (6−1)! = 5! = 120 ways. What is the probability that person ‘a’ will have person ‘b’ sat to his immediate left, and person ‘c’ sat to his immediate right? I’m confused on how to go about this.

How to calculate the probability of round table seating?

There are $6$ people, let’s call them – (a,b,c,d,e,f), to sit at a round table. The number of ways they can arrange themselves is $(6-1)! = 5! = 120$ ways. What is the probability that person ‘a’ will have person ‘b’ sat to his immediate left, and person ‘c’ sat to his immediate right? I’m confused on how to go about this. probabilitypermutations

What are the odds against two specified persons sitting next to each other?

A party of n persons sit at a round table. What are the odds against two specified persons sitting next to each other? The total number of circular permutations of n people taken all at a time, N = (n – 1)! Let event A = Two specified people sit together.

How many distinct arrangements are there at a round table?

There are $5!$ distinct arrangements of six people around the table since there are six identical rotations of each arrangement, giving $$\\frac{6!}{6} = 5!$$ arrangements.$\\endgroup$– N. F. TaussigOct 9 ’14 at 22:22 1